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Genetics Assignment

Table 3 All ANSWERS (INCLUDING P VALUES) MUST BE CORRECT TO 4 SIGNIFICANT FIGURES (1 mark each correct answer – note selective marking may apply) Characteristi c Population 1 Population 2 Population 3 1) µ = 132.0 mm µ = 140.8 mm µ = 126.7 mm Leaf length s.e. = 2.768 s.e. = 1.737 s.e. = 2.442 min = 75.00 min = 95.00 min = 72.00 max = 237.0 max = 185.0 max = 180.0 From your ANOVA table what is the P value: 0.0001326 Is there a significant difference between populations (Yes or No) YES 2) µ = 29.52 mm µ = 19.30 mm µ = 17.80 mm Leaf width s.e. = 0.5254 s.e. = 0.4299 s.e. = 0.2211 min = 13.00 min = 13.00 min = 8.000 max = 46.00 max = 31.00 max = 22.00 From your ANOVA table what is the P value 1.335e-67 Is there a significant difference between populations (Yes or No) YES 3) µ = 21.06 mm µ = 13.94 mm µ = 9.480 mm Length to tip s.e. = 0.7431 s.e. = 0.5280 s.e. = 0.2985 of 1st serration min = 8.000 min = 4.000 min = 4.000 max = 49.00 max = 31.00 max = 18.00 From your ANOVA table what is the P value 1.290e-38 Is there a significant difference between populations (Yes or No) YES 4) µ = 1.930 mm µ = 1.0496 mm µ = 0.5376 mm Pollen presenter length s.e. = 0.01579 s.e. = 0.02469 s.e. = 0.007506 min = 1.400 min = 0.6000 min = 0.3000 max = 2.400 max = 1.700 max = 0.7000 From your ANOVA table what is the P value 1.248e-184 Is there a significant difference between populations (Yes or No) YES 5) µ = 17.86 mm µ = 21.70 mm µ = 26.79 mm Seed width s.e. = 0.1517 s.e. = 0.2729 s.e. = 0.1735 Genetics 300845 Banksia hybridisation last updated February2015 min = 15.00 min = 16.00 min = 21.00 max = 27.00 max = 38.00 max = 36.00 From your ANOVA table what is the P value 9.537e-103 Is there a significant difference between populations (Yes or No) YES 6) µ = 31.54 mm µ = 36.42 µ = 42.29 Seed length s.e. = 0.1616 s.e. = 0.2556 s.e. = 0.1733 min = 22.00 min = 30.00 min = 38.00 max = 35.00 max = 45.00 max = 49.00 From your ANOVA table what is the P value 3.878e-128 Is there a significant difference between populations (Yes or No) YES Questions (Q1-3 Hint: compare your summary data to the species descriptions in Table 1) Q1. Which population (1, 2 or 3) is B. serrata? (2 marks) ________ Population 1 Q2. Which population (1, 2 or 3) is B. aemula? (2 marks) ________ Population 2 Q3. Which population (1, 2 or 3) is of hybrid origin? (2 marks) ____ Population 3 Q4. In order from the best (1) to worst (6) or least useful, which characteristic (e.g. leaf length or seed width) was the best in discriminating or distinguishing between the species B. serrata and B. aemula? (Hint: look at your ANOVA table (in particular your F and P values) and your max and min values for each characteristic). (6 marks) 1. Pollen presenter length 2. Leaf width 3. Seed length 4. Seed width 5. Length to tip of first serration 6. Leaf Length Q5. Name one characteristic that showed a quantitative difference (2 marks) Pollen presenter length Genetics 300845 Banksia hybridisation last updated February2015 Q6. Name one characteristic that showed a qualitative difference (2 marks) Leaf length Genetics 300845 Banksia hybridisation last updated February2015


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Genetics Assignment Help Service

HelpWithAssignment provides thorough genetics assignment help and genetics homework help. All the problems and calculations surrounding DNA structure and Genetics assignments can be easily dealt by our genetics assignment experts. Our experts are PhD academicians and professional scientists working in the fields of genetics and are well equipped to work on your college level genetics assignments.

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About Genetics and Genetics Assignment:

Are you struggling with your Genetics Assignment ? Are you a high school, college or graduate level student? Do you need Genetics Homework Help or Biology Assignment Help ? Our highly qualified, professional and skilled team members can provide you help with the topics listed below. 

Definition: Genetics is the study of hereditary or inheritance. Gregor Johann Mendel is considered as the father of Genetics.  This branch specially deals with mechanism, transmission, and the variation of inherited characteristics among similar or related organisms. This involves the understanding of various terms, such as DNA (deoxyribonucleic acid) a molecule which consists of all cells blueprint for Genetic Inheritance (Genes). 

According to the Mendel’s observation in his experiments:

  • The principle of Aggregation
  • The principle of Independent Assortment.

 As Mendel came with four conclusions for the above mentioned experiments such as,

  • The inheritance of each trait is determined by “units” or “factors” (now called genes) that are passed on to descendants unchanged.
  • An individual inherits one such unit from each parent for each trait.
  • A trait may not show up in an individual but can still be passed on to the next generation.
  • The genes for each trait segregate themselves during gamete production


There few characteristics about Genetics those are as follows: 

Genetics and Hereditary: Hereditary transforms genetic characteristics from ancient ancestor through genes to descendant. Basically genetics is concerned with hereditary to a distinguished characteristic that is passed down from one generation to the next. It’s not possible to separate Genetics and Hereditary from the body. As Hereditary begins with a cell, the information carried is within the cell nucleus. This is the control center and it contains chromosomes. These thread like structures are the genetic information which is organized in a DNA molecule. 

DNA: A DNA determines the characteristics of the entire organism which contains genetic material. The Structure, type and functions of a cell are influenced by chromosomes that are found in the nucleus of a cell. These are chromosomes are composed of DNA. 

Structure of DNA: DNA is composed of two strands of building blocks called nucleotides, which are arranged as a stair case. Each Nucleotide includes three parts such as, a Phosphate group, a Sugar Molecule and one of four bases (a) Adenine (b) Guanine (c) Cytosine (d) Thymine. The Sugar Phosphate bonds form the double back bone of the molecule. The key to genetic DNA is found in the steps of the stairs case, as the nitrogen containing bases. The bases linkup using hydrogen bonds using it in a specific way. Adenine with only bonds with Thymine A to T and Cytosine only bonds with Guanine C to G.  While these basic paring never change.

There are many more sub branches in Genetics, for which HelpwithAssignment Team provides Online Tutoring and assignment help are as follows: 

  • Genetic burden Assignment Help
  • Genetic code Assignment Help
  • Genetic drift Assignment Help
  • Genetic engineering Assignment Help
  • Genetic information Assignment Help
  • Genetic linkage Assignment Help
  • Genetic map Assignment Help
  • Genetic material Assignment Help
  • Genetic recombination Assignment Help
  • Genetic variation Assignment Help 

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